Tue, 29 Dec 2015
This article shows how to do design for Double Pipe Heat Exchanger and estimate length of double pipe required.Determine Heat Load
Obtain flowrate (W ), inlet, outlet temperatures and fouling factor for both hot and cold stream. Calculate physical properties like density (ρ), viscosity (μ), specific heat (Cp) and thermal conductivity (k) at mean temperature. Determine heat load by energy balances on two streams.
Q = mH.CpH(THot In - THot Out)
= mC.CpC(tCold Out - tCold In)
mH , mC: Mass flow rate of Hot and Cold Stream
CpH , CpC: Specific Heat of Hot and Cold Stream
THot In , THot Out: Inlet and outlet temperature of Hot Stream
tCold In , tCold Out: Inlet and outlet temperature of Cold Stream
LMTD = (ΔT1 - ΔT2)/ln( ΔT1 / ΔT2)
For Counter-current flow
ΔT1 = THot In - tCold Out
ΔT2 = THot Out - tCold In
For Co-current flow
Calculate Film Coefficient
ΔT1 = THot In - tCold In
ΔT2 = THot Out - tCold Out
Allocate hot and cold streams either in inner tube or annular space. General criteria for fluid placement in inner tube is corrosive fluid, cooling water, fouling fluid, hotter fluid and higher pressure stream. Calculate equivalent diameter (De) and flow area (Af) for both streams.Inner Tube
De = Di
Af = π Di²/4
De = D1 - Do
Af = π (D1² - Do²)/4
Di : Inside Pipe Inner Diameter
Do : Inside Pipe Outer Diameter
D1 : Outside Pipe Inner Diameter
Calculate velocity (V), Reynolds No. (Re) and Prandtl No. (Pr) number for each stream.
V = W / ( ρ Af )
Re = De V ρ / μ
Pr = Cp μ / k
For first iteration a Length of double pipe exchanger is assumed and heat transfer coefficient is calculated. Viscosity correction factor (μ / μw)0.14 due to wall temperature is considered 1.
For Laminar Flow (Re <= 2300), Seider Tate equation is used.
Nu = 1.86 (Re.Pr.De/L )1/3(μ/ μw)0.14
For Transient & Turbulent Flow (Re > 2300), Petukhov and Kirillov equation modified by Gnielinski can be used.
Nu = (f/8)(Re - 1000)Pr(1 + De/L)2/3/[1 + 12.7(f/8)0.5(Pr2/3 - 1)]*(μ/μw)0.14
f = (0.782* ln(Re) - 1.51)-2
L : Length of Double Pipe Exchanger
μw : Viscosity of fluid at wall temperature
Nu : Nusselts Number (h.De / k)
Wall temperature is calculated as following.
TW = (hitAve + hoTAveDo/Di)/(hi + hoDo/Di)
hi : Film coefficient Inner pipe
ho : Film coefficient for Annular pipe
tAve : Mean temperature for Inner pipe fluid stream
TAve : Mean temperature for Annular fluid stream
Viscosity is calculated for both streams at wall temperature and heat transfer coefficient is multiplied by viscosity correction factor.Overall Heat Transfer Coefficient
Overall heat transfer coefficient (U) is calculated as following.
1/U = Do/hi.Di + Do.ln(Do/Di)/2kt + 1/ho+ Ri.Do/Di + Ro
Ri : Fouling factor Inner pipe
Ro : Fouling factor for Annular pipe
kt : Thermal conductivity of tube material
Calculate Area and length of double pipe exchanger as following.
Area = Q / (U * LMTD )
L = Area / π * Do
Compare this length with the assumed length, if considerable difference is there use this length and repeat above steps, till there is no change in length calculated.
Number of hair pin required is estimated as following.
Calculate Pressure Drop
N Hairpin = L / ( 2 * Length Hairpin )
Pressure drop in straight section of pipe is calculated as following.
ΔPS = = f.L.G²/(7.5x1012.De.SG.(μ/ μw)0.14)
ΔP : Pressure Drop in PSI
SG : Specific Gravity of fluid
G : Mass Flux ( W / Af ) in lb/h.ft²
For Laminar flow in inner pipe, friction factor can be computed as following.
f = 64/Re
For Laminar flow in annular pipe.
f = (64 / Re) * [ (1 - κ²) / ( 1 + κ² + (1 - κ²) / ln κ) ]
κ = Do / D1
For turbulent flow in both pipe and annular pipe
Pressure Drop due to Direction Changes
f = 0.3673 * Re -0.2314
For Laminar Flow
ΔPR = 2.0x10-13. (2NHairpin - 1 ).G²/SG
For Turbulent Flow
Total Pressure Drop
ΔPR = 1.6x10-13. (2NHairpin - 1 ).G²/SG
ΔPTotal = ΔPS + ΔPR