Gravity Settling Separation

Gravity Settling Separation

This article illustrates determination of terminal velocity required for gravity separation. Performing a force balance on liquid droplet settling out of gas stream results in following relationship.

force balance on liquid droplet

where FB is force due to Buoyancy, FD is force due to Drag and FG is force due to gravity.

 FG = m.g
 FB = m.ρV.g/ρL
 FD = CD.(ρV.Vt²/2).AP

Assuming spherical liquid droplet with diameter DP, above equation gets reduced to

 FD = FG - FB
 FD = CD.(ρV.Vt²/2).(π.DP²/4)
 FG - FB = m.g(ρL - ρV)/ρL
 m = 4/3.(π.DP³/8).ρL

Balancing above equation gives following relation for terminal velocity Vt.

 Vt = [(4gDP/ 3CD).(ρL - ρV)/ρV ]0.5

Drag coefficient depends on shape of particle and Reynold’s number and can be determined from below graph.

Drag coefficient versus Reynold's number

Above curve can be simplified into 3 sections resulting into 3 settling laws.

Stoke’s Law

At low Reynold’s number < 2, a linear relationship exists between CD and Re.

 CD = 24/Re
 Re = DPV.VtV
 Vt = g.DP².(ρL - ρV)/18μV

In English units, with DP in feet, Vt in feet/sec, ρ in lb/ft³, g = 32.2 feet/sec² and μ in centipoise, above equation can be expressed as.

 Vt = 1488.g.DP².(ρL - ρV)/18μV

Criterion K is defined to determine the flow regime as following.

 K = DP[g.ρVL - ρV)/μV²]1/3

Value of K is evaluated for Reynold’s number 2 based on Stoke’s Law.

 Re = 2
 Vt = 2.μV/(ρV.DP)
 K = (36)1/3
 K = 3.3

For K < 3.3 Stoke’s Law is applicable.

Intermediate Law

For 2 < Re < 500, Intermediate law applies.

 CD = 18.5/Re0.6
 Vt = 0.153 g 0.71 DP 1.14L - ρV)0.71/ ( ρV0.29. μV0.43)

In English units, with viscosity in centipoise, above equation can be expressed as

 Vt = 3.49 g 0.71 DP 1.14L - ρV)0.71/ ( ρV0.29. μV0.43)

Newton’s Law

Newton’s law is applicable for Reynold’s number in range of 500 to 200,000.

 CD = 0.44
 Vt = 1.74 (g.DPL - ρV)/ ρV)0.5

Value of K is evaluated for Reynold’s number 500 based on Newton’s Law.

 Re = 500
 K = (500/1.74)2/3
 K = 43.5

For K in the range of 3.3 to 43.5, Intermediate Law is applicable; for K > 43.5, Newton’s Law is applied.

Stoke’s Law is applicable for vapor separation from a continuous liquid phase and dispersed liquid separation from a continuous liquid phase. Intermediate Law is typically used for liquid separation from a continuous vapor phase.

Calculate diameter for a vertical vapor liquid separator based on gravity separation. Gas flowrate is 50,000 lb/h, density is 3.7 lb/ft³ and viscosity is 0.01 cP. Liquid flowrate is 12,000 lb/h, density is 51.5 lb/ft³ and viscosity is 0.42 cP. Assume liquid particle diameter DPL as 250 micron and vapor particle diameter DPV as 150 micron.

Terminal velocity is to be calculated for gravity settling of liquid droplet from vapor phase. K Value is calculated to determine the applicable flow regime.

 K = 41.1

Intermediate Law is applicable for this case. Terminal velocity is calculated based on Intermediate Law.

 Vt = 0.96 feet/sec

Margin of 75% is taken on terminal velocity and vessel diameter is calculated.

 D1 = 2.58 feet

A second terminal velocity is calculated for disentraining vapor from liquid phase. Typically Stoke’s law is applicable for vapor disentrainment. Terminal velocity is calculated based on Stoke’s law.

 Vt = 0.07 feet/sec

With margin of 75% on terminal velocity, vessel diameter is calculated.

 D2 = 1.22 feet

Comparing both diameter values, highest value of 2.58 feet is selected as a minimum diameter required for gravity separation of vapor and liquid.

Spreadsheet for Determining diameter of Vertical Vapor Liquid Separator based on Gravity Separation

One Reply to “Gravity Settling Separation”

  1. Vt = 3.49 g 0.71 DP 1.14 (ρL – ρV)0.71/ ( ρV0.29. μV0.43). Please verify the constant 3.49, it has been written as 3.54 in several references.

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